Suppose you attempt to cook a hot dog by inserting a nail into each end of the hot dog and wrapping a wire around each nail, and then you insert the wires into the wall outlet.
The hotdog cooks, but the lights in your house go out.
Why is this so?
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Edward - said
September 20 2010 @ 16:38
The lights are not going out unless you short out the wires.
The salt and moisture in the hot dog allow for current to flow trough. The speed at which the hot dog will cook is proportional to the square of the voltage and inversely proportional to the hot dog resistance.
So power is
P=E/t= V^2/R
Where
E- energy (joules)
t- time (sec)
V- voltage (V)
R- resistance of the hot dog
then the time it will take the hot dog to heat up is
t= E R/ V^2
where the energy required is
E=Q= m Cp(T2-T1)
Rainbow - said
September 20 2010 @ 16:38
well , I dont know of a reason for the lights to go out in your house
but the little lights in your head would
because two wires being held while having voltage from a current touching metal might kill you
railroad dave - said
September 20 2010 @ 16:38
you need a rheostat to slow the shorting .
your mom - said
October 24 2011 @ 08:41
im not smart!!!